若方程√x^2-1￣=x+m无实数解，求m的取值范围

√x^2-1￣=x+m,两边平方得
x^2-1=(x+m)^2
2mx+m^2+1=0
x=-(m^2+1)/2m
当x+m<0或x^2-1<0时,方程无解
x<m,
-(m^2+1)/2m<-m
m>0时，-m^2-1<-2m^2
m^2<1
0<m<1---------------(1)
m<0时，-m^2-1>-2m^2
m^2>1
m<-1---------------(2)
x^2-1<0
(m^2+1)^2/4m^2<1
(m^2+1)^2<1-4m^2
m^2(m^2+6)<0无解
综上所述，m的取值范围为
0<m<1或m<-1